What is the sum of the first 555 terms of the geometric series 1,23,49 ...?1,23,49 ...?1,23,49 ...?


Answer:

211812118121181

Step by Step Explanation:
  1. The sum of first nnn terms of a G.P.G.P.G.P. is given by,
    Sn=a(1rn)(1r)Sn=a(1rn)(1r)Sn=a(1rn)(1r)
    Here, the first term, a=1a=1a=1 and
    the common ratio, r=ak+1ak where k1r=ak+1ak where k1r=ak+1ak where k1
    r=231=23r=231=23r=231=23
  2. The sum of first nnn terms of this G.P.G.P.G.P. is given by,
    [Math Processing Error] Now, the sum of the first 55 terms of the G.PG.P is given by, [Math Processing Error]
  3. Hence, the sum of the first 55 terms of the G.P.G.P. is 2118121181.

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