What is the sum of the first n terms of the geometric series 1,35,925 ...?
Answer:
52[1−(35)n]
- The sum of first n terms of a G.P. is given by,
Sn=a(1−rn)(1−r)
Here, the first term, a=1 and
the common ratio, r=ak+1ak where k≥1
⟹r=351=35 - The sum of first n terms of this G.P. is given by,
- Hence, the sum of the first terms of the is .